好きな３桁の数字を適当に思い浮かべて下さい｜2chコピペ保存道場
元の数＝100a+10b+cとすると2回続けて出来る数は
100000a+10000b+1000c+100a+10b+c
=100100a+10010b+1001c
=1001(100a+10b+c) ←1001で割り切れる（米１
=7*11*13(100a+10b+c)
よって、7だけでなく11・13でも割り切れる。
No.64647 | 2009-07-29 18:25 名無しのコピペ ◆mQop/nM
2009-11-02
(via twinleaves, sametimesameplace) (via an-k)
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